2x^3-5x^2+lnx=0

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Solution for 2x^3-5x^2+lnx=0 equation:


Simplifying
2x3 + -5x2 + lnx = 0

Reorder the terms:
lnx + -5x2 + 2x3 = 0

Solving
lnx + -5x2 + 2x3 = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '5x2' to each side of the equation.
lnx + -5x2 + 5x2 + 2x3 = 0 + 5x2

Combine like terms: -5x2 + 5x2 = 0
lnx + 0 + 2x3 = 0 + 5x2
lnx + 2x3 = 0 + 5x2
Remove the zero:
lnx + 2x3 = 5x2

Add '-2x3' to each side of the equation.
lnx + 2x3 + -2x3 = 5x2 + -2x3

Combine like terms: 2x3 + -2x3 = 0
lnx + 0 = 5x2 + -2x3
lnx = 5x2 + -2x3

Divide each side by 'nx'.
l = 5n-1x + -2n-1x2

Simplifying
l = 5n-1x + -2n-1x2

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